Problem #6-1-23, with solution suggested by Mark Cate.

Here is the problem: find the area bounded by the [Graphics:Images/index_gr_1.gif]-axis and the curve [Graphics:Images/index_gr_2.gif].

Solution: switch [Graphics:Images/index_gr_3.gif] and [Graphics:Images/index_gr_4.gif] and find the area between the [Graphics:Images/index_gr_5.gif]-axis and the curve [Graphics:Images/index_gr_6.gif].

The zeros of this function can be found by factoring (by grouping):

[Graphics:Images/index_gr_7.gif], so the zeros are at [Graphics:Images/index_gr_8.gif].

[Graphics:Images/index_gr_9.gif]

[Graphics:Images/index_gr_10.gif]

[Graphics:Images/index_gr_11.gif]

We have two regions. We'll integrate and evaluate each region separately using absolute values.

[Graphics:Images/index_gr_12.gif] + [Graphics:Images/index_gr_13.gif]
[Graphics:Images/index_gr_14.gif] + [Graphics:Images/index_gr_15.gif]

Oh heck, I'll let Mathematica do it.

[Graphics:Images/index_gr_16.gif]
[Graphics:Images/index_gr_17.gif]
[Graphics:Images/index_gr_18.gif]
[Graphics:Images/index_gr_19.gif]

Taking absolute values gives [Graphics:Images/index_gr_20.gif]

[Graphics:Images/index_gr_21.gif]
[Graphics:Images/index_gr_22.gif]
[Graphics:Images/index_gr_23.gif]
[Graphics:Images/index_gr_24.gif]

The textbook has 331/4, which appears to be a typo. Notice that [Graphics:Images/index_gr_25.gif] which is bigger than 80 which is 16×5, which is the area of a box that bounds both regions. So that can't be right.

[Graphics:Images/index_gr_26.gif]

[Graphics:Images/index_gr_27.gif]

[Graphics:Images/index_gr_28.gif]


Converted by Mathematica      June 9, 1999