Problem #6-1-23, with solution suggested by Mark Cate.
Here is the problem: find the area bounded by the -axis and the curve
.
Solution: switch and
and find the area between the
-axis and the curve
.
The zeros of this function can be found by factoring (by grouping):
, so the zeros are at
.
![[Graphics:Images/index_gr_9.gif]](Images/index_gr_9.gif)
We have two regions. We'll integrate and evaluate each region separately using absolute values.
+
+
Oh heck, I'll let Mathematica do it.
![[Graphics:Images/index_gr_16.gif]](Images/index_gr_16.gif)
![[Graphics:Images/index_gr_18.gif]](Images/index_gr_18.gif)
Taking absolute values gives
![[Graphics:Images/index_gr_21.gif]](Images/index_gr_21.gif)
![[Graphics:Images/index_gr_23.gif]](Images/index_gr_23.gif)
The textbook has 331/4, which appears to be a typo. Notice that which is bigger than 80 which is 16×5, which is the area of a box that bounds both regions. So that can't be right.
![[Graphics:Images/index_gr_26.gif]](Images/index_gr_26.gif)